// Given an integer array A of size N. You need to count the number of special elements in the given array.

// A element is special if removal of that element make the array balanced.

// Array will be balanced if sum of even index element equal to sum of odd index element.

int Solution::solve(vector<int> &A) {

int n=A.size();

int od[n]={0}; int ev[n]={0};

od[0]=A[0]; if(n>=2) od[1]=od[0];

for(int i=2;i<n;i=i+2)

{

od[i]=od[i-2]+A[i];

if(i+1<n)

od[i+1]=od[i];

}

ev[0]=0;

if(n>=2) ev[1]=A[1];

if(n>=3) ev[2]=ev[1];

for(int i=3;i<n;i=i+2)

{

ev[i]=ev[i-2]+A[i];

if(i+1<n)

ev[i+1]=ev[i];

}

// for(int i=0;i<n;i++)

// cout<<od[i]<<" ";

// cout<<endl;

// for(int i=0;i<n;i++)

// cout<<ev[i]<<" ";

// cout<<endl;

int cp=0;

for(int i=0;i<n;i++)

{

int odd=0,even=0;

if(i%2==0)

{

odd=od[i]-A[i];

odd+=ev[n-1]-ev[i];

even=ev[i]+od[n-1]-od[i];

}

else

{

even=ev[i]-A[i];

even+=od[n-1]-od[i];

odd=od[i]+ev[n-1]-ev[i];

}

if(odd==even)

cp++;

}

return cp;

}