// Given two strings S and T, determine if they are both one edit distance apart.

public class Solution {

public boolean isOneEditDistance(String s, String t) {

//iterate through the length of the smaller string

for(int i = 0; i < Math.min(s.length(), t.length()); i++) {

//if the current characters of the two strings are not equal

if(s.charAt(i) != t.charAt(i)) {

//return true if the remainder of the two strings are equal, false otherwise

if(s.length() == t.length()) {

return s.substring(i + 1).equals(t.substring(i + 1));

}

//return true if the strings would be the same if you deleted a character from string t

else if(s.length() < t.length()) {

return s.substring(i).equals(t.substring(i + 1));

}

//return true if the strings would be the same if you deleted a character from string s

else {

return t.substring(i).equals(s.substring(i + 1));

}

}

}

//if all characters match for the length of the two strings check if the two strings' lengths do not differ by more than 1

return Math.abs(s.length() - t.length()) == 1;

}

}